The decreasing order of boiling points of the following hydrides is
A.
$$Sb{H_3} > As{H_3} > P{H_3} > N{H_3}$$
B.
$$N{H_3} > Sb{H_3} > As{H_3} > P{H_3}$$
C.
$$Sb{H_3} > N{H_3} > As{H_3} > P{H_3}$$
D.
$$P{H_3} > As{H_3} > Sb{H_3} > N{H_3}$$
Answer :
$$Sb{H_3} > N{H_3} > As{H_3} > P{H_3}$$
Solution :
$$N{H_3}$$ has abnormally high boiling points because of their tendency to form hydrogen bonds. The order of boiling point will be $$Sb{H_3} > N{H_3} > As{H_3} > P{H_3}$$
Releted MCQ Question on Inorganic Chemistry >> P - Block Elements
Releted Question 1
The reddish brown coloured gas formed when nitric oxide is oxidised by air is