Question

The correct order of increasing basicity of the given conjugate bases $$\left( {R = C{H_3}} \right)$$   is

A. $$RCO\overline O < HC \equiv \overline C < \overline R < \overline N {H_2}$$
B. $$\overline R < HC \equiv \overline C < RCO\overline O < \overline N {H_2}$$
C. $$RCO\overline O < \overline N {H_2} < HC \equiv \overline C < \overline R $$
D. $$RCO\overline O < HC \equiv \overline C < \overline N {H_2} < \overline R $$  
Answer :   $$RCO\overline O < HC \equiv \overline C < \overline N {H_2} < \overline R $$
Solution :
The correct order of basicity is $$RCO\overline O < CH \equiv {C^ - } < N{H_2} - < {R^ - }$$

Releted MCQ Question on
Organic Chemistry >> General Organic Chemistry

Releted Question 1

The bond order of individual carbon-carbon bonds in benzene is

A. one
B. two
C. between one and two
D. one and two alternately
Releted Question 2

Molecule in which the distance between the two adjacent carbon atoms is largest is

A. Ethane
B. Ethene
C. Ethyne
D. Benzene
Releted Question 3

Among the following, the compound that can be most readily sulphonated is

A. benzene
B. nitrobenzene
C. toluene
D. chlorobenzene
Releted Question 4

The compound 1, 2-butadiene has

A. only $$sp$$   hybridized carbon atoms
B. only $$s{p^2}$$ hybridized carbon atoms
C. both $$sp$$  and $$s{p^2}$$ hybridized carbon atoms
D. $$sp$$ , $$s{p^2}$$ and $$s{p^3}$$ hybridized carbon atoms

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