Question
The bond between carbon atom (1) and carbon atom (2) in compound $$N = \mathop C\limits_1 - \mathop {CH}\limits_2 = C{H_2}$$ involves the hybrids as
A.
$$s{p^2}\,{\text{and}}\,s{p^2}$$
B.
$$s{p^{3\,}}{\text{and}}\,sp$$
C.
$$sp\,{\text{and}}\,s{p^2}$$
D.
$$sp\,{\text{and}}\,sp$$
Answer :
$$sp\,{\text{and}}\,s{p^2}$$
Solution :
Carbon bonded with a triple bond $$\left( {i.e.\,\,{C_1}} \right)$$ is $$sp$$ hybridised. Carbon bonded with a double bond $$\left( {{C_2}} \right)\,$$ is $$s{p^2}$$ hybridised.