Question
The actinoids exhibit more number of oxidation states in general than the lanthanoids. This is because
A.
the $$5f$$ orbitals extend further from the nucleus than the $$4f$$ orbitals
B.
the $$5f$$ orbitals are more buried than the $$4f$$ orbitals
C.
there is a similarity between $$4f$$ and $$5f$$ orbitals in their angular part of the wave function
D.
the actinoids are more reactive than the lanthanoids.
Answer :
the $$5f$$ orbitals extend further from the nucleus than the $$4f$$ orbitals
Solution :
NOTE: More the distance between nucleus and outer orbitals, lesser will be force of attraction on them. Distance between nucleus and $$5f$$ orbitals is more as compared to distance between $$4f$$ orbital and nucleus. So actinoids exhibit more number of oxidation states in general than the lanthanoids.