Question
Tertiary butyl bromide on reaction with sodium methoxide mainly gives
A.
$$tert$$ - butyl ethyl ether
B.
2 - methylpropene
C.
propene
D.
$$iso$$ - propyl alcohol
Answer :
2 - methylpropene
Solution :
\[{{H}_{3}}C\underset{\begin{smallmatrix}
| \\
\,\,\,C{{H}_{3}}
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,Br \\
|
\end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{3}}+C{{H}_{3}}ONa\to \] \[{{H}_{3}}C\underset{\begin{smallmatrix}
|\,\,\, \\
\,C{{H}_{3}}
\end{smallmatrix}}{\mathop{-C=}}\,C{{H}_{2}}+C{{H}_{3}}OH+NaBr\]