Question

Sulphur $$ = 35\left( {34.96903\,u} \right)$$    emits a $$\beta $$ - particle but no $$\gamma - ray.$$  The product is chlorine $$ = 35\,\left( {34.96885\,u} \right).$$    The maximum energy emitted by the $$\beta $$ - particle is

A. 16.758$$\,MeV$$
B. 1.6758$$\,MeV$$
C. 0.16758$$\,MeV$$  
D. 0.016758$$\,MeV$$
Answer :   0.16758$$\,MeV$$
Solution :
\[\underset{\left( Mass=34.96903\,u \right)}{\mathop{_{16}{{S}^{35}}}}\,\,\xrightarrow{-\beta }\,\underset{\left( Mass=34.96885\,u \right)}{\mathop{_{17}C{{l}^{35}}}}\,\]
$$\eqalign{ & {\text{Mass defect}} = \left( {34.96903 - 34.96885} \right)\,u \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 0.00018\,u \cr & {\text{Energy emitted}} = 0.00018 \times 931\,MeV \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 0.16758\,MeV \cr} $$

Releted MCQ Question on
Physical Chemistry >> Nuclear Chemistry

Releted Question 1

A nuclide of an alkaline earth metal undergoes radioactive decay by emission of three $$\alpha $$ - particles in succession. The group of the periodic table to which the resulting daughter element would belong is

A. group 14
B. group 16
C. group 4
D. group 6
Releted Question 2

The radioactive isotope $$_{27}C{o^{60}}$$  which is used in the treatment of cancer can be made by $$(n, p)$$  reaction. For this reaction the target nucleus is

A. $$_{28}N{i^{59}}$$
B. $$_{27}C{o^{59}}$$
C. $$_{28}N{i^{60}}$$
D. $$_{27}C{o^{60}}$$
Releted Question 3

The radio isotope, tritium $$\left( {_1{H^3}} \right)$$  has a half-life of $$12.3$$  $$yr.$$  If the initial amount of tritium is $$32$$ $$mg,$$  how many milligrams of it would remain after $$49.2$$  $$yr?$$

A. 4$$\,mg$$
B. 8$$\,mg$$
C. 1$$\,mg$$
D. 2$$\,mg$$
Releted Question 4

$$_{92}{U^{235}}$$  nucleus absorb a neutron and disintegrate in $$_{54}X{e^{139}},{\,_{38}}S{r^{94}}$$   and $$X,$$  so what will be the product $$X ?$$

A. 3-neutrons
B. 2-neutrons
C. $$\alpha $$ -particle
D. $$\beta $$ -particle

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Nuclear Chemistry


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