Sodium nitrate on reduction with $$Zn$$  in presence of $$NaOH$$  solution produces $$N{H_3}.$$  Mass of sodium nitrate absorbing $$1\,mole$$  of electron will be

Solution :
Ammonia is formed by reduction of nitrates and nitrites with $$Zn$$  and $$NaOH.\,\, Zn$$    and caustic soda produce nascent hydrogen which reacts with nitrates to form ammonia.
\[NaN{{O}_{3}}+8{{H}^{+}}+8{{e}^{-}}\xrightarrow{Zn/NaOH}NaOH+N{{H}_{3}}+2{{H}_{2}}O\]
From the equation,
Mass of \[8\,moles\]   of electron absorbs \[85\,g\,NaN{{O}_{3}}\]
∴ Mass of $$1\,mole$$  of electron absorbs $$\frac{{85}}{8} = 10.625\,g$$    of $$NaN{O_3}.$$