Question
Pentene-1 with $$HCl$$ gives
A.
3-chloropentane
B.
2-chloropentane
C.
1, 2-dichloropentane
D.
1-chloropentane
Answer :
2-chloropentane
Solution :
\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CH=C{{H}_{2}}\xrightarrow{HCl}\] \[C{{H}_{3}}-\underset{\begin{smallmatrix}
\,\,\,\,\,\,| \\
\,\,\,\,\,\,Cl
\end{smallmatrix}}{\mathop{C{{H}_{2}}C{{H}_{2}}CHC{{H}_{3}}}}\,\]