Oxidation number of sulphur in peroxomono-sulphuric acid $$\left( {{H_2}S{O_5}} \right)$$ is
A.
+ 4
B.
+ 2
C.
+ 6
D.
- 2
Answer :
+ 6
Solution :
\[{{H}_{2}}S{{O}_{5}};\,H-O-\underset{\begin{smallmatrix}
\downarrow \\
O
\end{smallmatrix}}{\overset{\begin{smallmatrix}
O \\
\uparrow
\end{smallmatrix}}{\mathop{S}}}\,-O-O-H\]
Oxidation number of $$O$$ in peroxo linkage = - 1
Oxidation number of other $$O$$ atoms = - 2
$$ + 2 + x - 6 - 2 = 0\,\,{\text{or}}\,\,x = + 6$$
Releted MCQ Question on Physical Chemistry >> Redox Reaction
Releted Question 1
Which of the following represents a redox reaction?
A.
$$NaOH + HCl \to NaCl + {H_2}O$$
B.
$$BaC{l_2} + {H_2}S{O_4} \to BaS{O_4} + 2HCl$$
C.
$$CuS{O_4} + 2{H_2}O \to Cu{\left( {OH} \right)_2} + {H_2}S{O_4}$$