On mixing a certain alkane with chlorine and irradiating it with ultraviolet light, it forms only one monochloroalkane. This alkane could be
A.
pentane
B.
isopentane
C.
neopentane
D.
propane
Answer :
neopentane
Solution :
In neopentane all the $$H$$ atoms are same $$\left( {{1^ \circ }} \right).$$
\[C{{H}_{3}}\underset{\begin{smallmatrix}
| \\
\,\,\,C{{H}_{3}}
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,\,\,\,C{{H}_{3}} \\
|
\end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{3}}\]
Releted MCQ Question on Organic Chemistry >> Hydrocarbons (Alkane, Alkene and Alkyne)