Question
One mole of $${N_2}{H_4}$$ loses $$10\,moles$$ of electrons to form a new compound, $$y.$$ Assuming that all nitrogen appear in the new compound, what is the oxidation state of nitrogen in $$y$$ ( There is no change in the oxidation state of hydrogen )
A.
$$-1$$
B.
$$-3$$
C.
$$+3$$
D.
$$+5$$
Answer :
$$+3$$
Solution :
\[\begin{align}
& \overset{-4}{\mathop{{{N}_{2}}}}\,\,\overset{+4}{\mathop{{{H}_{4}}}}\,\xrightarrow[N]{\text{loss}\,\,\text{of}\,{{10}_{e}}^{-}}\overset{+6}{\mathop{{{N}_{2}}}}\,Y; \\
& O.N.\,\,\text{of}\,N\,\text{changes from}\,-2\,\text{to}\,+3 \\
\end{align}\]