In $$Xe{F_2},Xe{F_4}$$ and $$Xe{F_6},$$ the number of lone pairs on $$Xe$$ are respectively
A.
2, 3, 1
B.
1, 2, 3
C.
4, 1, 2
D.
3, 2, 1
Answer :
3, 2, 1
Solution :
In $$Xe{F_2}$$ Total number of valence electrons of $$Xe = 8,$$ two electrons shared with $$2F$$ atoms, 6 electrons left hence 3 lone pairs, in $$Xe{F_4}4$$ shared with $$4 F$$ atoms 4 left hence 2 lone pairs; in $$Xe{F_6}6$$ shared with $$6 F$$ atoms 2 left hence 1 lone pair.
Releted MCQ Question on Inorganic Chemistry >> Chemical Bonding and Molecular Structure
Releted Question 1
The compound which contains both ionic and covalent bonds is