Question
In which of the following species the interatomic bond angle is $${190^0}\,\,{28'}$$ ?
A.
$$N{H_3},{\left( {B{F_4}} \right)^{ - 1}}$$
B.
$${\left( {N{H_4}} \right)^ + },B{F_3}$$
C.
$$N{H_3},B{F_4}$$
D.
$${\left( {N{H_2}} \right)^{ - 1}},B{F_3}.$$
Answer :
$$N{H_3},{\left( {B{F_4}} \right)^{ - 1}}$$
Solution :
In $$N{H_3}$$ and $$BF_4^ - $$ the hybridisation is $$s{p^3}$$ and the bond angle is almost $${190^0}\,\,{28'}.$$