Solution :
$$3B{r_2} + 6CO_3^{2 - } + 3{H_2}O \to 5B{r^ - } + BrO_3^ - + 6HCO_3^ - $$
$$O.N.$$ of $$B{r_2}$$ changes from 0 to $$–1$$ and $$+5$$ hence it is reduced as well as oxidised.
Releted MCQ Question on Physical Chemistry >> Redox Reaction
Releted Question 1
Which of the following represents a redox reaction?
A.
$$NaOH + HCl \to NaCl + {H_2}O$$
B.
$$BaC{l_2} + {H_2}S{O_4} \to BaS{O_4} + 2HCl$$
C.
$$CuS{O_4} + 2{H_2}O \to Cu{\left( {OH} \right)_2} + {H_2}S{O_4}$$