Question
In the reaction $$2PC{l_5} \rightleftharpoons PCl_4^ + + PCl_6^ - ,$$ the change in hybridisation is from
A.
$$s{p^3}d\,{\text{to}}\,s{p^3}\,{\text{and}}\,{\text{s}}{p^3}{d^2}$$
B.
$$s{p^3}d\,{\text{to}}\,s{p^2}\,{\text{and}}\,{\text{s}}{p^3}$$
C.
$$s{p^3}d\,{\text{to}}\,s{p^3}{d^2}\,{\text{and}}\,{\text{s}}{p^3}{d^3}$$
D.
$$s{p^3}{d^2}\,{\text{to}}\,s{p^3}\,{\text{and}}\,{\text{s}}{p^3}d$$
Answer :
$$s{p^3}d\,{\text{to}}\,s{p^3}\,{\text{and}}\,{\text{s}}{p^3}{d^2}$$
Solution :
$$\mathop {2PC{l_5}}\limits_{ \uparrow s{p^3}d} \rightleftharpoons \mathop {PCl_4^ + }\limits_{ \uparrow s{p^3}} + \mathop {PCl_6^ - }\limits_{ \uparrow s{p^3}{d^2}} $$