In the following reaction.
\[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}+4H\xrightarrow{\text{Red}\,\,P+HI}2X+{{H}_{2}}O\,;X\] is
A.
ethane
B.
ethylene
C.
butane
D.
propane
Answer :
ethane
Solution :
Ethers are reduced by red $$P$$ and $$HI$$ to alkanes through alkyl iodides \[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\xrightarrow{\text{red}\,\,P+HI}2{{C}_{2}}{{H}_{5}}I\xrightarrow{\text{red}\,\,P+HI}2{{C}_{2}}{{H}_{6}}\]
Releted MCQ Question on Organic Chemistry >> Alcohol, Phenol and Ether
Releted Question 1
Ethyl alcohol is heated with conc $${H_2}S{O_4}$$ the product formed is
A.
\[{{H}_{3}}C\underset{\begin{smallmatrix}
\parallel \\
O
\end{smallmatrix}}{\mathop{-C-}}\,O{{C}_{2}}{{H}_{5}}\]