Question
In Solvay ammonia process, sodium bicarbonate is precipitated due to
A.
presence of $$N{H_3}$$
B.
reaction with $$C{O_2}$$
C.
reaction with brine solution
D.
reaction with $$NaOH$$
Answer :
reaction with brine solution
Solution :
In Solvay ammonia process, sodium bicarbonate is precipitated due to common ion $$\left( {N{a^ + }} \right)$$ effect provided by brine ( concentrated $$NaCl$$ solution ).
$$N{H_4}HC{O_3} + NaCl + N{H_4}Cl$$ $$ + NaHC{O_3} \downarrow $$