In preparation of alkene from alcohol using $$A{l_2}{O_3},$$ which is effective factor?
A.
Porosity of $$A{l_2}{O_3}$$
B.
Temperature
C.
Concentration
D.
Surface area of $$A{l_2}{O_3}$$
Answer :
Temperature
Solution :
Temperature is the effective factor for dehydration of alcohol by $$A{l_2}{O_3}$$ ( dehydrating reagent ).
\[R-C{{H}_{2}}-C{{H}_{2}}OH\xrightarrow[{{350}^{\circ }}-{{380}^{\circ }}C]{A{{l}_{2}}{{O}_{3}}}R-CH=C{{H}_{2}}+{{H}_{2}}O\]
While at $${220^ \circ } - {250^ \circ }C,$$ it forms ether.
Releted MCQ Question on Organic Chemistry >> Alcohol, Phenol and Ether
Releted Question 1
Ethyl alcohol is heated with conc $${H_2}S{O_4}$$ the product formed is
A.
\[{{H}_{3}}C\underset{\begin{smallmatrix}
\parallel \\
O
\end{smallmatrix}}{\mathop{-C-}}\,O{{C}_{2}}{{H}_{5}}\]