Question
In Hofmann bromamide degradation, one of the important steps is the migration of
A.
an alkyl group without its electron pair to electron deficient $$N$$ atom.
B.
an alkyl group with its electron pair to electron deficient $$O$$ atom.
C.
an alkyl group with its electron pair to electron rich $$N$$ atom.
D.
an alkyl group with its electron pair to electron deficient $$N$$ atom.
Answer :
an alkyl group with its electron pair to electron deficient $$N$$ atom.
Solution :
For this one should remember that Hofmann’s degradation involves migration to electron deficient nitrogen atom, hence the alkyl group will migrate with its bonding pair of electrons.
For this one should remember that Hofmann’s degradation involves migration to electron deficient nitrogen atom, hence the alkyl group will migrate with its bonding pair of electrons.