Question
In Freundlich adsorption isotherm, the value of $$\frac{1}{n}$$ is
A.
between 0 and 1 in all cases
B.
between 2 and 4 in all cases
C.
1 in case of physical adsorption
D.
1 in case of chemisorption
Answer :
between 0 and 1 in all cases
Solution :
In Freundlich adsorption isotherm,
$$\frac{x}{m} = k{p^{\frac{1}{n}}}$$
Where, $$x =$$ amount of adsorbent
$$m=$$ amount of adsorbate
The value of $$n$$ is always greater than 1. So, the value of $$\frac{1}{n}$$ lies between 0 and 1 in all cases.