In Carius method of estimation of halogen, $$0.15\,g$$ of an organic compound gave $$0.12\,g$$ of $$AgBr.$$ What is the percentage of bromine in the compound?
A.
$$68.08\% $$
B.
$$34.04\% $$
C.
$$42.1\% $$
D.
$$50\% $$
Answer :
$$34.04\% $$
Solution :
Molar mass of $$AgBr = 108 + 80 = 188\,g\,mo{l^{ - 1}}$$
Percentage of $$B{r_2} = \frac{{80}}{{188}} \times \frac{{0.12}}{{0.15}} \times 100 = 34.04\% $$
Releted MCQ Question on Organic Chemistry >> General Organic Chemistry
Releted Question 1
The bond order of individual carbon-carbon bonds in
benzene is