In Bohr series of lines of hydrogen spectrum, the third line from the red end corresponds to which one of the following inter-orbit jumps of the electron for Bohr orbits in an atom of hydrogen
A.
$$5 \to 2$$
B.
$$4 \to 1$$
C.
$$2 \to 5$$
D.
$$3 \to 2$$
Answer :
$$5 \to 2$$
Solution :
The lines falling in the visible region comprise Balmer series. Hence the third line from red would be $${n_1} = 2,\,\,{n_2} = 5$$ i.e. $$5 \to 2.$$
Releted MCQ Question on Physical Chemistry >> Atomic Structure
Releted Question 1
The number of neutrons in dipositive zinc ion with mass number 70 is