In an experiment, addition of $$4.0\,ml$$ of $$0.005\,M$$ $$BaC{l_2}$$ to $$16.0\,ml$$ of arsenius sulphide sol just causes the complete coagulation in 2 hrs. The
flocculating value of the effective ion is
A.
$$C{l^ - },1.0$$
B.
$$C{l^ - },2.0$$
C.
$$B{a^{2 + }},1.0$$
D.
$$B{a^{2 + }},0.5$$
Answer :
$$B{a^{2 + }},1.0$$
Solution :
$$A{s_2}{S_3}$$ sol is negatively charged owing to preferential adsorption of $${S^{2 - }}\,ions.$$ Cation would be the effective ion in coagulation. Flocculating value = minimum milli $$mol$$ of the effective ion per litre of sol $$ = \frac{{4 \times 0.005 \times {{10}^3}}}{{4 + 16}} = 1.0$$
Releted MCQ Question on Physical Chemistry >> Surface Chemistry