Question

If 3 - hexanone is reacted with \[NaB{{H}_{4}}\]   followed by hydrolysis with \[{{D}_{2}}O,\]  the product will be

A. $$C{H_3}C{H_2}CH\left( {OH} \right)C{H_2}C{H_2}C{H_3}$$
B. $$C{H_3}C{H_2}CD\left( {OH} \right)C{H_2}C{H_2}C{H_3}$$
C. $$C{H_3}C{H_2}CH\left( {OD} \right)C{H_2}C{H_2}C{H_3}$$  
D. $$C{H_3}C{H_2}CD\left( {OD} \right)C{H_2}C{H_2}C{H_3}$$
Answer :   $$C{H_3}C{H_2}CH\left( {OD} \right)C{H_2}C{H_2}C{H_3}$$
Solution :
Remember that during reduction with $$NaB{H_4},$$  a hydride ion is transferred by $$NaB{H_4}$$  to carbonyl carbon and a proton ( or deutron ) is transferred from the solvent ( in the second step ) to carbonyl oxygen.
Aldehyde and Ketone mcq solution image

Releted MCQ Question on
Organic Chemistry >> Aldehyde and Ketone

Releted Question 1

The reagent with which both acetaldehyde and acetone react easily is

A. Fehling’s reagent
B. Grignard reagent
C. Schiff’s reagent
D. Tollen’s reagent
Releted Question 2

The Cannizzaro reaction is not given by

A. trimethylacetaldehye
B. acetaldehyde
C. benzaldehyde
D. formaldehyde
Releted Question 3

The compound that will not give iodoform on treatment with alkali and iodine is :

A. acetone
B. ethanol
C. diethyl ketone
D. isopropyl alcohol
Releted Question 4

Polarisation of electrons in acrolein may be written as

A. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = CH - \mathop {CH}\limits^{{\delta ^ + }} = O$$
B. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = CH - CH = \mathop O\limits^{{\delta ^ + }} $$
C. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = \mathop {CH}\limits^{{\delta ^ + }} - CH = O$$
D. $$\mathop {C{H_2}}\limits^{{\delta ^ + }} = CH - CH = \mathop O\limits^{{\delta ^ - }} $$

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Aldehyde and Ketone


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