Question
Identify $$X$$ and $$Y$$ in the following reaction.
\[\underset{\begin{smallmatrix}
\,\,\,\,\,\,| \\
\,\,\,\,\,\,\,Br
\end{smallmatrix}}{\mathop{{{H}_{2}}C}}\,-\underset{\begin{smallmatrix}
|\,\,\,\,\,\,\,\, \\
Br\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,+KOH\xrightarrow{\text{ alcohol}}\] \[X\xrightarrow{NaN{{H}_{2}}}Y\]
|
$$X$$ |
$$Y$$ |
| (a) |
$$C{H_3}C{H_2}Br$$ |
$$C{H_2} = C{H_2}$$ |
| (b) |
$$C{H_2}OH - C{H_2}OH$$ |
$$C{H_2} = C{H_2}$$ |
| (c) |
$$C{H_2} = CHBr$$ |
$$CH \equiv CH$$ |
| (d) |
$$CH \equiv CBr$$ |
$$CH \equiv CH$$ |
A.
(a)
B.
(b)
C.
(c)
D.
(d)
Answer :
(c)
Solution :
\[\underset{\begin{smallmatrix}
\,\,\,\,\,\,| \\
\,\,\,\,\,\,\,Br
\end{smallmatrix}}{\mathop{{{H}_{2}}C}}\,-\underset{\begin{smallmatrix}
|\,\,\,\,\,\,\,\,\, \\
Br\,\,\,\,\,\,\,\,
\end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,\xrightarrow[\begin{smallmatrix}
-KBr \\
-{{H}_{2}}O
\end{smallmatrix}]{alc.\,KOH}\] \[\underset{\left( X \right)}{\mathop{C{{H}_{2}}=CHBr}}\,\xrightarrow[\begin{smallmatrix}
-NaBr \\
-N{{H}_{3}}
\end{smallmatrix}]{NaN{{H}_{2}}}\underset{\left( Y \right)}{\mathop{CH\equiv CH}}\,\]