Question
For a first-order reaction, the half-life period is independent of
A.
initial concentration
B.
cube root of initial concentration
C.
first power of final concentration
D.
square root of final concentration
Answer :
initial concentration
Solution :
$${t_{\frac{1}{2}}}\,\,{\text{of}}\,\,{n^{th}}\,\,{\text{order reaction}} \propto \frac{1}{{{a^{n - 1}}}}$$
where, $$a=$$ initial concentration of reactant
$$n=$$ order of reaction
$$\therefore \,\,{t_{\frac{1}{2}}}$$ for first order reaction $$\left( {n = 1} \right)$$
$$\eqalign{
& {t_{\frac{1}{2}}} \propto \frac{1}{{{a^{1 - 1}}}} \cr
& {\text{or}}\,\,\,{t_{\frac{1}{2}}} \propto \frac{1}{{{a^0}}}\,\,\,\,\left( {{a^0} = 1} \right) \cr} $$
So, for a first order reaction half-life is independent on initial concentration of reactants.