Question
$$\eqalign{
& A + {H_2}O \to B + HCl \cr
& B + {H_2}O \to C + HCl \cr} $$
Compound $$(A), (B)$$ and $$(C)$$ will be respectively :
A.
$$PC{l_5},POC{l_3},{H_3}P{O_3}$$
B.
$$PC{l_5},POC{l_3},{H_3}P{O_4}$$
C.
$$SOC{l_2},POC{l_3},{H_3}P{O_3}$$
D.
$$PC{l_3},POC{l_3},{H_3}P{O_4}$$
Answer :
$$PC{l_5},POC{l_3},{H_3}P{O_4}$$
Solution :
$$\eqalign{
& \mathop {PC{l_5}}\limits_{\left( A \right)} + {H_2}O \to \mathop {POC{l_3}}\limits_{\left( B \right)} + 2HCl \cr
& \mathop {POC{l_3}}\limits_{\left( B \right)} + 3{H_2}O \to \mathop {{H_3}P{O_4}}\limits_{\left( C \right)} + 3HCl \cr} $$