Question
Electronic configuration of calcium atom can be written as
A.
$$\left[ {Ne} \right]4{p^2}$$
B.
$$\left[ {Ar} \right]4{s^2}$$
C.
$$\left[ {Ne} \right]4{s^2}$$
D.
$$\left[ {Kr} \right]4{p^2}$$
Answer :
$$\left[ {Ar} \right]4{s^2}$$
Solution :
To write the electronic configuration of an atom, it is better if we remember the atomic number of noble gases and the orbitals follow the noble gas. The atomic number of $$Ca$$ is 20 and its nearest noble gas is argon $$(Ar = 18).$$
Hence, the electronic configuration of $$Ca = \left[ {Ar} \right]4{s^2}.$$