$${E^ \circ }$$ for $$\frac{{C{l_2}}}{{C{l^ - }}} = + 1.36,\frac{{{I_2}}}{{{I^ - }}} = + 0.53,$$ $$\frac{{A{g^ + }}}{{Ag}} = + 0.79,\frac{{N{a^ + }}}{{Na}} = - 2.71$$ and $$\frac{{L{i^ + }}}{{Li}} = - 3.04\,V.$$ What is the order of decreasing reducing strength for these species?
A.
$$Li > C{l^ - } > Ag > {I^ - } > Na$$
B.
$$Li > Na > {I^ - } > Ag > C{l^ - }$$
C.
$$C{l^ - } > Ag > {I^ - } > Na > Li$$
D.
$$Na > Li > Ag > C{l^ - } > {I^ - }$$
Answer :
$$Li > Na > {I^ - } > Ag > C{l^ - }$$
Solution :
The order is $$Li > Na > {I^ - } > Ag > C{l^ - }.$$
Releted MCQ Question on Inorganic Chemistry >> S - Block Elements
Releted Question 1
A substance absorbs $$C{O_2}$$ and voilently reacts with water. The substance is