Question
During the charging of lead storage battery, the reaction at anode is represented by :
A.
$$P{b^{2 + }} + SO_4^{2 - } \to PbS{O_4}$$
B.
$$PbS{O_4} + 2{H_2}O \to $$ $$Pb{O_2} + SO_4^{2 - } + 4{H^ + } + 2{e^ - }$$
C.
$$Pb \to P{b^{2 + }} + 2{e^ - }$$
D.
$$P{b^{2 + }} + 2{e^ - } \to Pb$$
Answer :
$$PbS{O_4} + 2{H_2}O \to $$ $$Pb{O_2} + SO_4^{2 - } + 4{H^ + } + 2{e^ - }$$
Solution :
During charging, the lead storage battery behaves like an electrolytic cell. So, at anode the reaction is $$PbS{O_4} + 2{H_2}O \to $$ $$Pb{O_2} + 4{H^ + } + SO_4^{2 - } + 2{e^ - }$$