$$CuS{O_4}$$ is paramagnetic while $$ZnS{O_4}$$ is diamagnetic because
A.
$$C{u^{2 + }}$$ ion has $$3{d^9}$$ configuration while $$Z{n^{2 + }}$$ ion has $$3{d^{10}}$$ configuration
B.
$$C{u^{2 + }}$$ ion has $$3{d^5}$$ configuration while $$Z{n^{2 + }}$$ ion has $$3{d^6}$$ configuration
C.
$$C{u^{2 + }}$$ has half filled orbitals while $$Z{n^{2 + }}$$ has fully filled orbitals
D.
$$CuS{O_4}$$ is blue in colour while $$ZnS{O_4}$$ is white
Answer :
$$C{u^{2 + }}$$ ion has $$3{d^9}$$ configuration while $$Z{n^{2 + }}$$ ion has $$3{d^{10}}$$ configuration
Releted MCQ Question on Inorganic Chemistry >> D and F Block Elements
Releted Question 1
When same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volume of hydrogen evolved is