Consider the ground state of $$Cr$$  atom ( $$X$$ = 24 ). The number of electrons with the azimuthal quantum numbers, $$\ell = 1$$  and 2 are, respectively

Solution :
Electronic configuration of $$Cr$$ atom ( $$z$$ = 24)
$$\eqalign{ & = 1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^5},4{s^1} \cr & \operatorname{When} \,\ell = 1,\,p - {\text{subshell}}, \cr & {\text{Numbers}}\,{\text{of}}\,{\text{electrons}} = 12 \cr & {\text{when}}\,\ell = 2,\,d{\text{ - subshell}}, \cr & {\text{Numbers}}\,{\text{of}}\,{\text{electrons}} = 5 \cr} $$