Question

$$\left[ {Co{{\left( {N{H_3}} \right)}_4}{{\left( {N{O_2}} \right)}_2}} \right]Cl$$      exhibits

A. linkage isomerism, ionization isomerism and geometrical isomerism  
B. ionization isomerism, geometrical isomerism and optical isomerism
C. linkage isomerism, geometrical isomerism and optical isomerism
D. linkage isomerism, ionization isomerism and optical isomerism
Answer :   linkage isomerism, ionization isomerism and geometrical isomerism
Solution :
The given compound may have linkage isomerism due to presence of $$N{O_2}$$  group which may be in the form $$ - N{O_2}$$  or $$ - ONO.$$  $$\left[ {Co{{\left( {N{H_3}} \right)}_4}{{\left( {N{O_2}} \right)}_2}} \right]Cl$$     $$\& \left[ {CO{{\left( {N{H_3}} \right)}_4}{{\left( {ONO} \right)}_2}} \right]Cl$$      It may have ionisation isomerism due to presence of two ionisable groups $$ - N{O_2}$$  $$\& - Cl.$$
$$\left[ {Co{{\left( {N{H_3}} \right)}_4}Cl\left( {N{O_2}} \right)} \right]N{O_2}$$      $$\& \left[ {Co\left( {N{H_3}} \right){{\left( {N{O_2}} \right)}_2}} \right]Cl$$      It may have geometrical isomerism in the form of cis trans form as follows :
Co-ordination Compounds mcq solution image

Releted MCQ Question on
Inorganic Chemistry >> Co - ordination Compounds

Releted Question 1

Amongst $$Ni{\left( {CO} \right)_4},{\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}{\text{and}}\,NiCl_4^{2 - }$$

A. $$Ni{\left( {CO} \right)_4}\,{\text{and}}\,NiCl_4^{2 - }$$     are diamagnetic and $${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$   is paramagnetic
B. $$NiCl_4^{2 - }\,{\text{and}}\,{\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$     are diamagnetic and $$Ni{\left( {CO} \right)_4}$$   is paramagnetic
C. $$Ni{\left( {CO} \right)_4}\,{\text{and}}\,{\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$     are diamagnetic and $$NiCl_4^{2 - }$$  is paramagnetic
D. $$Ni{\left( {CO} \right)_4}$$  is diamagnetic and $$NiCl_4^{2 - }\,{\text{and}}\,{\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$     are paramagnetic
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Releted Question 2

The geometry of $$Ni{\left( {CO} \right)_4}\,{\text{and}}\,Ni{\left( {PP{h_3}} \right)_2}C{l_2}\,{\text{are}}$$

A. both square planar
B. tetrahedral and square planar, respectively
C. both tetrahedral
D. square planar and tetrahedral, respectively
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Releted Question 3

The complex ion which has no $$'d'$$ electron in the central metal atom is

A. $${\left[ {Mn{O_4}} \right]^ - }$$
B. $${\left[ {Co{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }}$$
C. $${\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{3 - }}$$
D. $${\left[ {Cr{{\left( {{H_2}O} \right)}_6}} \right]^{3 + }}$$
View Answer
Releted Question 4

In the process of extraction of gold,
Roasted gold ore $$ + C{N^ - } + {H_2}O\mathop \to \limits^{{O_2}} \left[ X \right] + O{H^ - }$$
$$\left[ X \right] + Zn \to \left[ Y \right] + Au$$
Identify the complexes $$\left[ X \right]\,\,{\text{and}}\,\,\left[ Y \right]$$

A. $$X = {\left[ {Au{{\left( {CN} \right)}_2}} \right]^ - },Y = {\left[ {Zn{{\left( {CN} \right)}_4}} \right]^{2 - }}$$
B. $$X = {\left[ {Au{{\left( {CN} \right)}_4}} \right]^{3 - }},Y = {\left[ {Zn{{\left( {CN} \right)}_4}} \right]^{2 - }}$$
C. $$X = {\left[ {Au{{\left( {CN} \right)}_2}} \right]^ - },Y = {\left[ {Zn{{\left( {CN} \right)}_6}} \right]^{4 - }}$$
D. $$X = {\left[ {Au{{\left( {CN} \right)}_4}} \right]^ - },Y = {\left[ {Zn{{\left( {CN} \right)}_4}} \right]^{2 - }}$$
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Co - ordination Compounds

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