Reaction would be 100% complete only after infinite time which cannot be calculated.
272.
The rate of a reaction doubles when its temperature changes from $$300 K$$ to $$310 K.$$ Activation energy of such a reaction will be : $$\left( {R = 8.314\,J{K^{ - 1}}mo{l^{ - 1}}\,{\text{and}}\,\log 2 = 0.301} \right)$$
273.
For a reaction, $${A_2} + {B_2} \rightleftharpoons 2AB$$ the figure shows the path of the reaction in absence and presence of a catalyst. What will be the energy of activation for forward $$\left( {{E_f}} \right)$$ and backward $$\left( {{E_b}} \right)$$ reaction in presence of a catalyst and $$\Delta H$$ for the reaction? The dotted curve is the path of reaction in presence of a catalyst.
A
$${E_f} = 60\,kJ/mol,{E_b} = 70\,kJ/mol,$$ $$\Delta H = 20\,kJ/mol$$
B
$${E_f} = 20\,kJ/mol,{E_b} = 20\,kJ/mol,$$ $$\Delta H = 50\,kJ/mol$$
C
$${E_f} = 70\,kJ/mol,{E_b} = 20\,kJ/mol,$$ $$\Delta H = 10\,kJ/mol$$
D
$${E_f} = 10\,kJ/mol,{E_b} = 20\,kJ/mol,$$ $$\Delta H = - 10\,kJ/mol$$
274.
A radioactive isotope having a half - life period of 3 days was received after 12 days. If $$3g$$ of the isotope is left in the container, what would be the initial mass of the isotope?
275.
For the reaction, $$2{N_2}{O_5} \to 4N{O_2} + {O_2},$$ the rate
equation can be expressed in two ways $$ - \frac{{d\left[ {{N_2}{O_5}} \right]}}{{dt}} = k\left[ {{N_2}{O_5}} \right]$$ and $$ + \frac{{d\left[ {N{O_2}} \right]}}{{dt}} = k'\left[ {{N_2}{O_5}} \right]$$ $$k$$ and $$k'$$ are related as :
TIPS/Formulae :
$$N = {N_0}{\left( {\frac{1}{2}} \right)^n}$$
where, $$N=$$ Amount of radioactive substance which is left after certain number of half-life periods $$(n)$$
$${N_0} = $$ Initial amount of radioactive substance.
$$\eqalign{
& {\text{No}}{\text{. of half - lives = }}\frac{{{\text{total}}\,{\text{time}}}}{{{\text{half}}\,{\text{life}}\,{\text{period}}}} \cr
& = \frac{{560}}{{140}} \cr
& = 4 \cr} $$
In $$‘n’$$ half-lives, the element will reduce to
$$\eqalign{
& {\left( {\frac{1}{2}} \right)^n} \times {\text{Initial}}\,{\text{wt}}{\text{.}} \cr
& {\text{ = }}{\left( {\frac{1}{2}} \right)^4} \times 1 \cr
& = \frac{1}{{16}}g \cr} $$
277.
The rate constant of a zero order reaction is $$2.0 \times {10^{ - 2}}mol\,{L^{ - 1}}{s^{ - 1}}.$$ If the concentration of the reactant after 25 seconds is $$0.5\,M.$$ What is the initial concentration?
280.
The rate equation for a reaction,
$${N_2}O \to {N_2} + \frac{1}{2}{O_2}$$
is Rate $$ = k{\left[ {{N_2}O} \right]^0} = k.$$ If the initial concentration of the reactant is $$a\,mol\,Li{t^{ - 1}},$$ the half-life period of the reaction is