221.
\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}\xrightarrow[h\upsilon ]{C{{l}_{2}}}\] \[\underset{\begin{smallmatrix}
\text{(monochlorination} \\
\text{products) }
\end{smallmatrix}}{\mathop{A+B\,\,\,\,\,\,\,\,\,\,\,\,}}\,\]
The approximate ratio of percentage yields of $$A$$ and $$B$$ formed in the above reaction is
In neopentane all the $$H$$ atoms are same $$\left( {{1^ \circ }} \right).$$
\[C{{H}_{3}}\underset{\begin{smallmatrix}
| \\
\,\,\,C{{H}_{3}}
\end{smallmatrix}}{\overset{\begin{smallmatrix}
\,\,\,\,\,C{{H}_{3}} \\
|
\end{smallmatrix}}{\mathop{-C-}}}\,C{{H}_{3}}\]
224.
Some $$meta$$ - directing substituents in aromatic substitution are given. Which one is most deactivating?
228.
At 300 K and 1 atm, 15 mL of a gaseous hydrocarbon requires $$375 mL$$ air containing 20% $${O_2}$$ by volume for complete combustion. After combustion the gases occupy $$330 mL.$$ Assuming that the water formed is in liquid form and the volumes were measured at the same temperature and pressure, the formula of the hydrocarbon is :
Boiling points of alkanes increase as the number of carbon atom increases or molecular mass increases. Alkenes have high boiling point, so $$C{H_3}C{H_2}C{H_2}C{H_3}$$ has the lowest boiling point.
230.
Ethane is formed during the formation of chloromethane by chlorination of methane because
A
higher members of the hydrocarbons are generally formed during reactions
B
two methyl free radicals may combine during chlorination to give ethane
C
two chloromethane molecules react to form ethane
D
chlorine free radical reacts with methane to give ethane
Answer :
two methyl free radicals may combine during chlorination to give ethane