$$BC{l_3} + 3{H_2}O \to {H_3}B{O_3} + 3HCl$$

$$A{l_2}{O_3}$$  is highly stable and passive to chemical reactions.

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(i) Structure of $$SiC{l_4}$$

Structure of $$PCl_4^ + $$

(ii) Diamond and silicon carbide $$(SiC),$$  both are isostructural because their central atom is $$s{p^3}$$  hybridised and both have tetrahedral arrangement.
(iii) Structure of $$N{H_3}$$

Structure of $$P{H_3}$$

Both $$N{H_3}$$  and $$P{H_3}$$  have $$s{p^3}$$  geometry.
(iv) $$Xe{F_4}$$  has $$s{p^3}{d^2}$$  hybridisation while $$Xe{O_4}$$  has $$s{p^3}$$  hybridisation.
Structure of $$Xe{F_4}$$

Structure of $$Xe{O_4}$$

Hence, $$Xe{F_4}$$  and $$Xe{O_4}$$  are not isostructural.

Quartz is the crystalline form of silica $$\left( {Si{O_2}} \right).$$  It is extensively used as a piezoelectric material.

$$P{H_3}$$  ( Lewis base ) can react with $${B_2}{H_6}$$  ( Lewis acid ).

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\[2AgCl{{O}_{3}}+C{{l}_{2}}\left( \text{dry} \right)\xrightarrow{\text{Heat}}\]     \[2AgCl+2Cl{{O}_{2}}+{{O}_{2}}\]

$$S{O_2}$$  is an angular molecule with $$O -S - O$$   bond angle of $${119.5^ \circ }.$$

The nitroprusside ion is $${\left[ {Fe{{\left( {CN} \right)}_6}N{O^ + }} \right]^{2 - }}.$$
The magnetic moment measurements reveal the presence of 4 unpaired electrons in $$Fe$$  which must be then in $$F{e^{2 + }}\left( {3{d^6}} \right)$$   and not $$F{e^{3 + }}\left( {3{d^5}} \right)$$