Question
\[C{{H}_{3}}C{{H}_{2}}Cl\xrightarrow{NaCN}X\xrightarrow{Ni/{{H}_{2}}}Y\xrightarrow[\text{anhydride}]{\text{Acetic}}Z\]
$$Z$$ in the above reaction sequence is
A.
$$C{H_3}C{H_2}C{H_2}NHCOC{H_3}$$
B.
$$C{H_3}C{H_2}C{H_2}N{H_2}$$
C.
$$C{H_3}C{H_2}C{H_2}CONHC{H_3}$$
D.
$$C{H_3}C{H_2}C{H_2}CONHCOC{H_3}$$
Answer :
$$C{H_3}C{H_2}C{H_2}NHCOC{H_3}$$
Solution :
\[\begin{align}
& C{{H}_{3}}C{{H}_{2}}Cl\xrightarrow{NaCN}\underset{\left( X \right)}{\mathop{C{{H}_{3}}C{{H}_{2}}CN}}\,\xrightarrow{Ni/{{H}_{2}}} \\
& \underset{\left( Y \right)}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}}}}\,\xrightarrow[{{\left( C{{H}_{3}}CO \right)}_{2}}O]{}\underset{\left( Z \right)}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}NHCOC{{H}_{3}}}}\,+C{{H}_{3}}COOH \\
\end{align}\]