Question
\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\xrightarrow[{{170}^{\circ }}C]{\text{conc}\text{.}\,{{H}_{2}}S{{O}_{4}}}\] \[A\xrightarrow[{{500}^{\circ }}C]{C{{l}_{2}}}B.\] $$A$$ and $$B$$ are
A.
$$A = C{H_3}C{H_2}C{H_3},B = C{H_3}C{H_2}C{H_2}Cl$$
B.
$$A = C{H_3}CH = C{H_2},$$ $$B = C{H_2}ClCH = C{H_2}$$
C.
$$A = C{H_2} = C{H_2},B = C{H_3}C{H_2}Cl$$
D.
$$A = C{H_3}C{H_2}C{H_3},B = C{H_3}CH = C{H_2}$$
Answer :
$$A = C{H_3}CH = C{H_2},$$ $$B = C{H_2}ClCH = C{H_2}$$
Solution :
\[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\xrightarrow[{{170}^{\circ }}C]{\text{conc}.\,{{H}_{2}}S{{O}_{4}}}\] \[\underset{'A'}{\mathop{C{{H}_{3}}CH=C{{H}_{2}}}}\,\xrightarrow[{{500}^{\circ }}C]{C{{l}_{2}}}\] \[\underset{'B'}{\mathop{C{{H}_{2}}ClCH=C{{H}_{2}}}}\,\]