Question
\[C{H_3} - C \equiv CH\xrightarrow[{1\% \,HgS{O_4}}]{{40\% \,{H_2}S{O_4}}}A\] \[\xrightarrow{\text{Isomerisation}}C{{H}_{3}}\underset{\begin{smallmatrix}
\parallel \\
O
\end{smallmatrix}}{\mathop{-C-}}\,C{{H}_{3}}\]
\[C{H_3} - C \equiv CH\xrightarrow[{1\% \,HgS{O_4}}]{{40\% \,{H_2}S{O_4}}}A\] \[\xrightarrow{\text{Isomerisation}}C{{H}_{3}}\underset{\begin{smallmatrix}
\parallel \\
O
\end{smallmatrix}}{\mathop{-C-}}\,C{{H}_{3}}\]
Structure of $$'A'$$ and type of isomerism in the above reaction are respectively
A.
prop-1-en-2-ol, metamerism
B.
prop-1-en-1-ol, tautomerism
C.
prop-2-en-2-ol, geometrical isomerism
D.
prop-1-en-2-ol, tautomerism
Answer :
prop-1-en-2-ol, tautomerism
Solution :
