$${\left( {C{H_3}} \right)_2}C = CHCOC{H_3}$$ can be oxidised to $${\left( {C{H_3}} \right)_2}C = CHCOOH$$ by
A.
$${\text{chromic acid}}$$
B.
$$NaOI$$
C.
$$Cu\,\,{\text{at}}\,\,{300^ \circ }C$$
D.
$$KMn{O_4}$$
Answer :
$$NaOI$$
Solution :
Haloform reaction,
$${\left( {C{H_3}} \right)_2}C = CHCOC{H_3}$$ contains unit so it can be oxidised to $${\left( {C{H_3}} \right)_2}C = CH - COOH$$ by $$NaOI.$$
Releted MCQ Question on Organic Chemistry >> Aldehyde and Ketone
Releted Question 1
The reagent with which both acetaldehyde and acetone react easily is