Question
$$N{H_4}Cl{O_4} + HN{O_3}\left( {dil.} \right) \to $$ $$HCl{O_4} + \left[ X \right]$$
\[\left[ X \right]\xrightarrow{\Delta }Y\left( g \right)\]
$$\left[ X \right]$$ and $$\left[ Y \right]$$ are respectively -
A.
$$N{H_4}N{O_3}\,\,\& \,\,{N_2}O$$
B.
$$N{H_4}N{O_2}\,\,\& \,\,{N_2}$$
C.
$$HN{O_4}\,\,\& \,\,{O_2}$$
D.
$${\text{None of these}}$$
Answer :
$$N{H_4}N{O_3}\,\,\& \,\,{N_2}O$$
Solution :
\[\begin{align}
& N{{H}_{4}}Cl{{O}_{4}}+HN{{O}_{3}}\to HCl{{O}_{4}}+\underset{\left( X \right)}{\mathop{N{{H}_{4}}N{{O}_{3}}}}\, \\
& N{{H}_{4}}N{{O}_{3}}\xrightarrow{\Delta }\underset{\left( Y \right)}{\mathop{{{N}_{2}}O}}\,+2{{H}_{2}}O \\
\end{align}\]