Arrange the following in increasing order of covalent character - $$NaCl,MgC{l_2},AlC{l_3}.$$
A.
$$NaCl < MgC{l_2} < AlC{l_3}$$
B.
$$MgC{l_2} < NaCl < AlC{l_3}$$
C.
$$AlC{l_3} < MgC{l_2} < NaCl$$
D.
$$NaCl < AlC{l_3} < MgC{l_2}$$
Answer :
$$NaCl < MgC{l_2} < AlC{l_3}$$
Solution :
Cation size is decreasing in the order : $$N{a^ + } > M{g^{2 + }} > A{l^{3 + }}$$
$$A{l^{3 + }}$$ has maximum polarisation effect and $$N{a^ + }$$ has minimum polarisation effect.
The covalent nature is in the order : $$AlC{l_3} > MgC{l_2} > NaCl$$
Releted MCQ Question on Inorganic Chemistry >> Chemical Bonding and Molecular Structure
Releted Question 1
The compound which contains both ionic and covalent bonds is