Question
Anhydrous aluminium chloride $$\left( {A{l_2}C{l_6}} \right)$$ is covalent compound and soluble in water giving :
A.
$$A{l^{3 + }}\,{\text{and}}\,C{l^ - }\,ions$$
B.
$${\left[ {Al{{\left( {{H_2}O} \right)}_6}} \right]^{3 + }}\,{\text{and}}\,C{l^ - }\,ions$$
C.
$${\left[ {AlC{l_2}{{\left( {{H_2}O} \right)}_4}} \right]^ + }{\text{and}}{\left[ {AlC{l_4}{{\left( {{H_2}O} \right)}_2}} \right]^ - }ions$$
D.
none of the above
Answer :
$${\left[ {AlC{l_2}{{\left( {{H_2}O} \right)}_4}} \right]^ + }{\text{and}}{\left[ {AlC{l_4}{{\left( {{H_2}O} \right)}_2}} \right]^ - }ions$$
Solution :
\[AlC{{l}_{3}}.6{{H}_{2}}O\xrightarrow{\text{dissociation}}{{\left[ AlC{{l}_{2}}{{\left( {{H}_{2}}O \right)}_{4}} \right]}^{+}}+{{\left[ AlC{{l}_{4}}{{\left( {{H}_{2}}O \right)}_{2}} \right]}^{-}}\]