Question
An organic compound $${C_6}{H_{12}}\left( X \right)$$ on reduction gives $${C_6}{H_{14}}\left( Y \right).$$ $$X$$ on ozonolysis gives two aldehydes $${C_2}{H_4}O\left( {\text{I}} \right)$$ and $${C_4}{H_8}O\left( {{\text{II}}} \right).$$ Identify the compounds $$X, Y$$ and aldehydes $$\left( {\text{I}} \right)$$ and $$\left( {{\text{II}}} \right).$$
A.
$$X = C{H_3}CH = CHC{H_2}C{H_2}C{H_3},$$ $$Y = C{H_3}{\left( {C{H_2}} \right)_4}C{H_3},$$ $$\left( {\text{I}} \right) = C{H_3}CHO,$$ $$\left( {{\text{II}}} \right) = C{H_3}{\left( {C{H_2}} \right)_2}CHO$$
B.
$$X = C{H_3}C{H_2}CH = CHC{H_2}C{H_3},$$ $$Y = C{H_3}{\left( {C{H_2}} \right)_4}C{H_3},$$ $$\left( {\text{I}} \right) = C{H_3}CHO,\left( {{\text{II}}} \right) = C{H_3}CHO$$
C.
$$X = C{H_3}C{H_2}C{H_2}C{H_2}CH = C{H_2},$$ $$Y = C{H_3}{\left( {C{H_2}} \right)_3}C{H_3},$$ $$\left( {\text{I}} \right) = HCHO,\left( {{\text{II}}} \right) = C{H_3}{\left( {C{H_2}} \right)_2}CHO$$
D.
\[X=C{{H}_{3}}C{{H}_{2}}\underset{\begin{smallmatrix}
|\,\,\, \\
\,C{{H}_{3}}
\end{smallmatrix}}{\mathop{-C=}}\,CH-C{{H}_{3}},\] \[Y=C{{H}_{3}}{{\left( C{{H}_{2}} \right)}_{3}}C{{H}_{3}},\] \[\left( \text{I} \right)=C{{H}_{3}}CHO,\left( \text{II} \right)=C{{H}_{3}}C{{H}_{2}}CHO\]
Answer :
$$X = C{H_3}CH = CHC{H_2}C{H_2}C{H_3},$$ $$Y = C{H_3}{\left( {C{H_2}} \right)_4}C{H_3},$$ $$\left( {\text{I}} \right) = C{H_3}CHO,$$ $$\left( {{\text{II}}} \right) = C{H_3}{\left( {C{H_2}} \right)_2}CHO$$
Solution :
