Question
Among the following, the correct order of acidity is
A.
$$HClO < HCl{O_2} < HCl{O_3} < HCl{O_4}$$
B.
$$HCl{O_2} < HClO < HCl{O_3} < HCl{O_4}$$
C.
$$HCl{O_4} < HCl{O_2} < HClO < HCl{O_3}$$
D.
$$HCl{O_3} < HCl{O_4} < HCl{O_2} < HClO$$
Answer :
$$HClO < HCl{O_2} < HCl{O_3} < HCl{O_4}$$
Solution :
As the oxidation state of halogen i.e. $$-Cl$$ in this case increases, acidity of oxyacid increases.
$$HClO:$$ Oxidation state of $$Cl = + 1$$
$$HCl{O_2}:$$ Oxidation state of $$Cl = + 3$$
$$HCl{O_3}:$$ Oxidation state of $$Cl = + 5$$
$$HCl{O_4}:$$ Oxidation state of $$Cl = + 7$$
Therefore, the correct order of acidity would be
$$HClO < HCl{O_2} < HCl{O_3} < HCl{O_4}$$