Question
Among the following ions the $$p\pi - d\pi $$ overlap could be present in
A.
$$NO_2^ - $$
B.
$$NO_3^ - $$
C.
$$PO_4^{3 - }$$
D.
$$CO_3^{2 - }$$
Answer :
$$PO_4^{3 - }$$
Solution :
In $$P–O$$ bond, $$\pi $$ bond is formed by the sidewise overlapping of $$d$$ - orbital of $$P$$ and $$p$$-orbital of oxygen. Hence it is formed by $$p\pi $$ and $$d\pi $$ overlapping.
In $$P–O$$ bond, $$\pi $$ bond is formed by the sidewise overlapping of $$d$$ - orbital of $$P$$ and $$p$$-orbital of oxygen. Hence it is formed by $$p\pi $$ and $$d\pi $$ overlapping.