All $$Cu\left( {{\text{II}}} \right)$$ halides are known except the iodide. The reason for it is that
A.
iodide is a bulky ion
B.
$$C{u^{2 + }}$$ oxidizes iodide to iodine
C.
$$Cu_{\left( {aq} \right)}^{2 + }$$ has much more negative hydration enthalpy
D.
$$C{u^{2 + }}$$ ion has smaller size
Answer :
$$C{u^{2 + }}$$ oxidizes iodide to iodine
Solution :
$$2C{u^{2 + }} + 4{I^ - } \to 2Cu{I_2}$$
The $$Cu{I_2}$$ immediately decomposes to liberate $${I_2}$$ and insoluble copper$$\left( {\text{I}} \right)$$ iodide.
$$2Cu{I_2} \to 2CuI + {I_2}$$
Releted MCQ Question on Inorganic Chemistry >> D and F Block Elements
Releted Question 1
When same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volume of hydrogen evolved is