A reaction in which reactants $$(R)$$ are converted into products $$(P)$$ follows second order kinetics. If concentration of $$R$$ is increased by four times, what will be the increase in the rate of formation of $$P?$$
A.
9 times
B.
4 times
C.
16 times
D.
8 times
Answer :
16 times
Solution :
$$R \to P$$
For a second order reaction, rate $$ = k{\left[ R \right]^2}$$
If conc. of $$R$$ is increased by four times, rate $$ = k{\left[ {4R} \right]^2}$$
Hence, the rate of formation of $$P$$ increases by 16 times.
Releted MCQ Question on Physical Chemistry >> Chemical Kinetics
Releted Question 1
If uranium (mass number 238 and atomic number 92) emits an $$\alpha $$ -particle, the product has mass no. and atomic no.