Question
A reaction attains equilibrium state under standard conditions, then what is incorrect for this ?
A.
Equilibrium constant $$K = 0$$
B.
Equilibrium constant $$K = 1$$
C.
$$\Delta {G^ \circ } = 0$$ and $$\Delta {H^ \circ } = T\Delta {S^ \circ }$$
D.
$$\Delta G = 0$$ and $$\Delta H = T\Delta S$$
Answer :
Equilibrium constant $$K = 0$$
Solution :
$$\Delta {G^ \circ } = 0$$ at equilibrium under standard state. Also at equilibrium, $$\Delta G = 0$$
$$\eqalign{
& \therefore \,\,\Delta {H^ \circ } - T\Delta {S^ \circ } = 0 \cr
& {\text{Also}},\Delta {G^ \circ } = 2.303\,RT\,\log \,K \cr
& \therefore \,\,K = 1\,\,{\text{when}}\,\,\Delta {G^ \circ } = 0 \cr} $$