Question

A metal $$X$$ reacts with aqueous $$NaOH$$ solution to form $$Y$$ and a highly inflammable gas. Solution $$Y$$ is heated and $$C{O_2}$$ is poured through it. $$Z$$ precipitates out and $$N{a_2}C{O_3}$$ is formed. $$Z$$ on heating gives $$A{l_2}{O_3}.$$ Identify $$X, Y$$ and $$Z.$$

$$X$$ $$Y$$ $$Z$$

(a) $$Al$$ $$NaAl{O_2}$$ $$Al{\left( {OH} \right)_3}$$

(b) $$A{l_2}{O_3}$$ $$NaAl{O_2}$$ $$A{l_2}C{O_3}$$

(c) $$A{l_2}{O_3}$$ $${\left[ {N{a_2}Al{O_2}} \right]^ + }O{H^ - }$$ $$Al{\left( {OH} \right)_3}$$

(d) $$Al$$ $$Al{\left( {OH} \right)_3}$$ $$A{l_2}{O_3}$$

A. (a)

B. (b)

C. (c)

D. (d)

Answer : (a)

Solution :
$$\mathop {2Al}\limits_{\left( X \right)} + 2NaOH + 2{H_2}O \to $$ $$\mathop {2NaAl{O_2}}\limits_{\left( Y \right)} + 3{H_2}$$
$$\mathop {2NaAl{O_2}}\limits_{\left( Y \right)} + C{O_2} + 3{H_2}O \to $$ $$\mathop {2Al{{\left( {OH} \right)}_3}}\limits_{\left( Z \right)} + N{a_2}C{O_3}$$
\[\underset{\left( Z \right)}{\mathop{2Al{{\left( OH \right)}_{3}}}}\,\xrightarrow{\Delta }A{{l}_{2}}{{O}_{3}}+3{{H}_{2}}O\]

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	$$X$$	$$Y$$	$$Z$$
(a)	$$Al$$	$$NaAl{O_2}$$	$$Al{\left( {OH} \right)_3}$$
(b)	$$A{l_2}{O_3}$$	$$NaAl{O_2}$$	$$A{l_2}C{O_3}$$
(c)	$$A{l_2}{O_3}$$	$${\left[ {N{a_2}Al{O_2}} \right]^ + }O{H^ - }$$	$$Al{\left( {OH} \right)_3}$$
(d)	$$Al$$	$$Al{\left( {OH} \right)_3}$$	$$A{l_2}{O_3}$$

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